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0=-16x^2+35x-18
We move all terms to the left:
0-(-16x^2+35x-18)=0
We add all the numbers together, and all the variables
-(-16x^2+35x-18)=0
We get rid of parentheses
16x^2-35x+18=0
a = 16; b = -35; c = +18;
Δ = b2-4ac
Δ = -352-4·16·18
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{73}}{2*16}=\frac{35-\sqrt{73}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{73}}{2*16}=\frac{35+\sqrt{73}}{32} $
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